TS EAMCET · Physics · Mechanical Properties of Solids
A metal rod of area of cross-section \(3 \mathrm{~cm}^2\) is stretched along its length by applying a force of \(9 \times 10^4 \mathrm{~N}\). If the Young's modulus of the material of the rod is \(2 \times 10^{11} \mathrm{Nm}^{-2}\), the energy stored per unit volume in the stretched rod is
- A \(13.5 \times 10^5 \mathrm{Jm}^{-3}\)
- B \(9 \times 10^5 \mathrm{Jm}^{-3}\)
- C \(2.25 \times 10^5 \mathrm{Jm}^{-3}\)
- D \(4.5 \times 10^5 \mathrm{Jm}^{-3}\)
Answer & Solution
Correct Answer
(C) \(2.25 \times 10^5 \mathrm{Jm}^{-3}\)
Step-by-step Solution
Detailed explanation
\( \sigma = \frac{F}{A} = \frac{9 \times 10^4 \mathrm{~N}}{3 \times 10^{-4} \mathrm{~m}^2} = 3 \times 10^8 \mathrm{~Pa} \)…
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