TS EAMCET · Physics · Nuclear Physics
The half-life of \({ }_{84}^{209} \mathrm{P}_0\) is 103 years. The time it takes for \(100 \mathrm{~g}\) sample of \({ }_{84}^{209} \mathrm{P}_0\) to decay to 3.125 \(\mathrm{g}\) is
- A 3296 years
- B \(103 \sqrt{2}\) years
- C 1648 years
- D 515 years
Answer & Solution
Correct Answer
(D) 515 years
Step-by-step Solution
Detailed explanation
In one half life, half of amount is decayed. So, decay occurs as
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