TS EAMCET · Physics · Oscillations
For a particle executing SHM, determine the ratio of average acceleration of the particle between extreme position and equilibrium position w.r.t. the maximum acceleration.
- A \(\frac{4}{\pi}\)
- B \(\frac{2}{\pi}\)
- C \(\frac{1}{\pi}\)
- D \(\frac{1}{2 \pi}\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{\pi}\)
Step-by-step Solution
Detailed explanation
Average acceleration of particle in SHM between extreme and equilibrium position is \(A_{\text {avg }}=\frac{\omega^2 a}{\pi / 2}=\omega^2 a \times \frac{2}{\pi}\left(\mathrm{ms}^{-2}\right)\) where, \(\omega^2 a=A_{\max }\) So,…
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