TS EAMCET · Physics · Dual Nature of Matter
Light strikes a metal surface causing photoelectric emission. The wavelength of incident light is \(248 \mathrm{~nm}\). If the stopping potential for the ejected electrons is \(2.8 \mathrm{eV}\), then the work function of the metal is (Take hc \(=1240 \mathrm{eV} . \mathrm{nm})\)
- A \(5.2 \mathrm{eV}\)
- B \(4.4 \mathrm{eV}\)
- C \(3.8 \mathrm{eV}\)
- D \(2.2 \mathrm{eV}\)
Answer & Solution
Correct Answer
(D) \(2.2 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
We have K.E. = E - W \[ \mathrm{K} . \mathrm{E}=\frac{\mathrm{hc}}{\lambda}-\mathrm{W} \] \[ \begin{aligned} & \mathrm{W}=\frac{\mathrm{hc}}{\lambda}-\mathrm{K} . \mathrm{E} \\ & =\frac{1240}{278}=2.8 \end{aligned} \] The work function of the metal, \(\mathrm{W}=2.2 \mathrm{eV}\)
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