TS EAMCET · Physics · Motion In One Dimension
A stone is thrown vertically up from the top end of a window of height 1.8 m with a velocity of \(8 \mathrm{~ms}^{-1}\). The time taken by the stone to cross the window during its downward journey is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A 0.8 s
- B 1.6 s
- C 1.0 s
- D 0.2 s
Answer & Solution
Correct Answer
(D) 0.2 s
Step-by-step Solution
Detailed explanation
Time to reach maximum height (A) from the top end of the window using \(\begin{aligned} & v=u+g t \text { or, } 0=8+-10 \times t \\ & \therefore \quad t=0.8 s \end{aligned}\) Height from top end of window to A using \(\mathrm{h}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^2\)…
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