TS EAMCET · Physics · Thermodynamics
Five moles of an ideal gas has pressure \(p_0\) volume \(V_0\) and temperature \(T_0\). The gas is expanded to volume \(3 V_0\) along a path, so that the pressure \(p\) is changed as function of volume \(V\) as \(p=p_0\left(V / V_0\right)\). The pressure is then reduced to \(p_0\) maintaining the volume constant. The gas undergoes an isobaric compression till the volume and temperature become \(V_0\) and \(T_0\), respectively. The total work done by the gas during the entire process is
- A \(p_0 V_0 / 3\)
- B \(3 p_0 V_0\)
- C \(5 p_0 V_0 / 3\)
- D \(2 p_0 V_0\)
Answer & Solution
Correct Answer
(D) \(2 p_0 V_0\)
Step-by-step Solution
Detailed explanation
The given situation is shown in the following diagram Work done in expansion (process I) \(=\int_{V_i}^{V_f} p d V=\int_{V_0}^{3 V_0} \frac{p_0 V}{V_0} \cdot d V\) \(=\frac{p_0}{V_0}\left[\frac{V^2}{2}\right]_{V_0}^{3 V_0}=\frac{p_0}{2 V_0}\left(9 V_0^2-V_0^2\right)=4 p_0 V_0\)…
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