TS EAMCET · Physics · Mechanical Properties of Fluids
Consider a water droplet of diameter \(0.2 \mathrm{~mm}\) where the outside pressure is \(1.5 \mathrm{~N} / \mathrm{cm}^2\) at \(25^{\circ} \mathrm{C}\). The pressure inside the droplet, when the surface tension at \(25^{\circ} \mathrm{C}\) is \(0.08 \mathrm{~N} / \mathrm{m}\) is
- A \(0.32 \mathrm{~N} / \mathrm{cm}^2\)
- B \(1.18 \mathrm{~N} / \mathrm{cm}^2\)
- C \(1.82 \mathrm{~N} / \mathrm{cm}^2\)
- D \(1.66 \mathrm{~N} / \mathrm{cm}^2\)
Answer & Solution
Correct Answer
(D) \(1.66 \mathrm{~N} / \mathrm{cm}^2\)
Step-by-step Solution
Detailed explanation
Given, diameter of water droplet, \(d=0.2 \mathrm{~mm}\) \(\therefore\) radius, \(r=0.1 \mathrm{~mm}=10^{-4} \mathrm{~m}\) Pressure outside droplet, \(p_0=1.5 \mathrm{~N} / \mathrm{cm}^2=1.5 \times 10^4 \mathrm{~N} / \mathrm{m}^2\) Surface tension,…
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