TS EAMCET · Physics · Gravitation
From the pole of the earth, a body of mass \(m\) is imparted a velocity \(v_0\) directed vertically up. If \(M\) is the mass of the earth, \(R\) its radius and \(g\) is the free-fall acceleration on its surface, then the height \(h\) to which the body will ascent is (neglect air resistance)
- A \(\frac{R v_0^2}{\left(2 g R-v_0^2\right)}\)
- B \(\frac{R v_0^2}{2 g R}\)
- C \(R\)
- D \(\frac{R v_0^2}{\left(2 g R+v_0^2\right)}\)
Answer & Solution
Correct Answer
(A) \(\frac{R v_0^2}{\left(2 g R-v_0^2\right)}\)
Step-by-step Solution
Detailed explanation
If body moves up to height \(h\), then by conservation of energy, we get…
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