TS EAMCET · Physics · Nuclear Physics
\(\alpha\)-decay of a parent nucleus \(\mathrm{X}\) results in a daughter nucleus Y. If \(m_x, m_y\) and \(m_a\) are the masses of the parent nucleus, the daughter nucleus and the \(\alpha\) - particle respectively, then the net kinetic.energy gained in the process is
- A \(\left(m_x+m_a-m_y\right) c^2\)
- B \(\left(m_x-m_y-m_a\right) c^2\)
- C \(\left(m_x+m_y+m_a\right) c^2\)
- D \(\left(m_x+m_y-m_a\right) c^2\)
Answer & Solution
Correct Answer
(B) \(\left(m_x-m_y-m_a\right) c^2\)
Step-by-step Solution
Detailed explanation
\({ }_2 \mathrm{He}^4+\mathrm{X} \rightarrow \mathrm{Y}\) The net kinetic energy gained in the process \(\Delta \mathrm{E}=\left(\mathrm{m}_{\mathrm{x}}+\mathrm{m}_{\mathrm{a}}-\mathrm{m}_{\mathrm{y}}\right) \mathrm{C}^2\)
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