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TS EAMCET · Physics · Capacitance

The following figure shows a 9Vbattery and3 uncharged capacitors of capacitances C1=C2=C3=1μF. The switch is thrown to the right side until capacitor C1is fully charged, then the switch is thrown to the left. The final charge on capacitor C2is

  1. A 1 μC
  2. B 2 μC
  3. C 3 μC
  4. D 4 μC
Verified Solution

Answer & Solution

Correct Answer

(C) 3 μC

Step-by-step Solution

Detailed explanation

Charge on capacitorC1=C1×9=9μC.Now when the switch is thrown to the leftside, charge distribution on left capacitors will be as given below, For parallel combination along pointAandB, potential drop across it will be same,QC1=qC2+qC3⇒Q=2qAlso, total charge in the brancheswill be…
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