TS EAMCET · Physics · Laws of Motion
A block of mass M moving on a frictionless horizontal surface collides with a spring of spring constant K, as shown in the figure. If the spring compresses by a length \(\mathrm{L}\), then the maximum momentum of the block after the collision is.

- A Zero
- B \(\frac{\mathrm{ML}^2}{\mathrm{~K}}\)
- C \(\mathrm{L} \sqrt{\mathrm{MK}}\)
- D \(\frac{\mathrm{KL}^2}{2 \mathrm{M}}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{L} \sqrt{\mathrm{MK}}\)
Step-by-step Solution
Detailed explanation
Initial kinetic energy, \(\mathrm{KE}=\frac{1}{2} \mathrm{Mv}^2\) Final potential energy, \(P E=\frac{1}{2} k^2\) from the conservation of energy K.E \(=\) P.E…
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