TS EAMCET · Physics · Semiconductors
Consider an amplifier circuit in which a transistor is used in common-emitter mode. The load resistance \(3 \mathrm{k} \Omega\). When a signal of \(30 \mathrm{mV}\) is added to base emitter voltage, the base current is changed by \(30 \mu \mathrm{A}\) and the collector current is changed by \(3 \mathrm{~mA}\). The power gain in this circuit will be
- A \(10000\)
- B \(20000\)
- C \(30000\)
- D \(40000\)
Answer & Solution
Correct Answer
(C) \(30000\)
Step-by-step Solution
Detailed explanation
Given, load resistance in common emitter mode, \(R=3 \mathrm{k} \Omega=3000 \Omega\) Input voltage, \(V_i=30 \mathrm{mV}\) Change in base current, \(\Delta I_B=30 \mu \mathrm{A}=3 \times 10^{-5} \mathrm{~A}\) Change in collector current,…
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