TS EAMCET · Physics · Motion In One Dimension
For a particle moving along a straight line path, the displacements in third and fifth seconds of its motion are 10 m and 18 m respectively. The speed of the particle at time \(\mathrm{t}=4 \mathrm{~s}\) is
- A \(32 \mathrm{~ms}^{-1}\)
- B \(8 \mathrm{~ms}^{-1}\)
- C \(12 \mathrm{~ms}^{-1}\)
- D \(16 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(D) \(16 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
\(s_n = u + a(n - 0.5)\) \(10 = u + 2.5a\) \(18 = u + 4.5a\) \((18 - 10) = (u + 4.5a) - (u + 2.5a) \Rightarrow 8 = 2a \Rightarrow a = 4 \text{ ms}^{-2}\) \(10 = u + 2.5(4) \Rightarrow 10 = u + 10 \Rightarrow u = 0 \text{ ms}^{-1}\) \(v_4 = u + at = 0 + 4(4) = 16 \text{ ms}^{-1}\)
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