TS EAMCET · Physics · Center of Mass Momentum and Collision
Collision takes place between two solid spheres denoted as 1 and 2 . The initial velocities of the spheres are \(u_1=3 \mathrm{~m} / \mathrm{s}\) and \(u_2=1.5 \mathrm{~m} / \mathrm{s}\) and the final velocities are \(v_1=2.5 \mathrm{~m} / \mathrm{s}\) and \(v_2=3.5 \mathrm{~m} / \mathrm{s}\). The coefficient of restitution between the materials of the spheres is nearly
- A 0.67
- B 0.78
- C 0.83
- D 0.96
Answer & Solution
Correct Answer
(A) 0.67
Step-by-step Solution
Detailed explanation
Coefficient of restitution, \[ \begin{aligned} & e=\frac{\text { Relative velocity of separation }}{\text { Relative velocity of approach }} \\ & \Rightarrow \quad e=\frac{v_2-v_1}{u_1-u_2}=\frac{3.5-25}{3-1.5}=\frac{1}{1.5}=\frac{2}{3}=0.67 \end{aligned} \]
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