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TS EAMCET · Physics · Wave Optics

The pass-axes of two polarisers were kept such that the incident unpolarised beam of intensity \(I_0\), gets completely blocked. Another polariser was introduced in between these two polarisers with its pass-axis \(60^{\circ}\) with respect to the pass-axis of the first one. The output intensity would then become

  1. A 0
  2. B \(\frac{3}{32} I_0\)
  3. C \(\frac{3}{16} I_0\)
  4. D \(\frac{3}{8} I_0\)
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Answer & Solution

Correct Answer

(B) \(\frac{3}{32} I_0\)

Step-by-step Solution

Detailed explanation

Since, the pass axes of two polarisers \(P_1\) and \(P_2\) were kept such that the incident unpolarised beam of intensity \(I_0\) gets completely blocked. This means that both polarisers were kept cross (perpendicular of their pass axes) to each other. When third polariser…
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