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TS EAMCET · Physics · Motion In Two Dimensions

A point \(P\) is moving in uniform circular motion with radius \(3 \mathrm{~m}\). Let at some instant the acceleration of the point is \(\mathbf{a}=(6 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}^2\), the position vector is \(\mathbf{r}\) and velocity vector is \(\mathbf{v}\). Choose the correct statement.

  1. A \(v \cdot a=0\) and \(r \times a \neq 0\)
  2. B \(v \cdot a \neq 0\) and \(r \times a \neq 0\)
  3. C \(v \cdot a=0\) and \(r \times a=0\)
  4. D \(v \cdot a \neq 0\) and \(r \times a=0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(v \cdot a=0\) and \(r \times a=0\)

Step-by-step Solution

Detailed explanation

The given situation is shown in the following figure Acceleration, \(\mathbf{a}=6 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}\) Clearly, acceleration \(\mathbf{a}\) is perpendicular to velocity \(\mathbf{v}\), hence \(\mathbf{v} \cdot \mathbf{a}=0\) Again, position vector \(\mathbf{r}\)…
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