TS EAMCET · Physics · Current Electricity
As shown in the figure, in a Wheatstone's bridge, three resistances \(\mathrm{P}, \mathrm{Q}\) and \(\mathrm{R}\) are connected in the three arms and the fourth arm is formed by two resistances \(S_1\) and \(S_2\) connected in parallel. The condition for the bridge to be balanced is
- A \(\frac{P}{Q}=\frac{2 R}{S_1+S_2}\)
- B \(\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}\left(\mathrm{S}_1+\mathrm{S}_2\right)}{\mathrm{S}_1 \mathrm{~S}_2}\)
- C \(\frac{P}{Q}=\frac{R\left(S_1+S_2\right)}{2 S_1 S_2}\)
- D \(\frac{P}{Q}=\frac{R}{S_1+S_2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}\left(\mathrm{S}_1+\mathrm{S}_2\right)}{\mathrm{S}_1 \mathrm{~S}_2}\)
Step-by-step Solution
Detailed explanation
Two resistance \(\mathrm{S}_1\) and \(\mathrm{S}_2\) connected in parallel. \[ \mathrm{S}=\frac{\mathrm{S}_1 \mathrm{~S}_2}{\mathrm{~S}_1+\mathrm{S}_2} \] from the wheat stone bridge…
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