TS EAMCET · Physics · Thermodynamics
An ideal gas goes through a process \(A \rightarrow B \rightarrow C \rightarrow A\) cycle. The process, \(A \rightarrow B\) is adiabatic. Calculate the work done in the process \(A \rightarrow B\).

- A \(p_0 V_0\)
- B \(\frac{p_0 V_0\left(2^{1 / \gamma}-2\right)}{(1-\gamma)}\)
- C \(p_0 V_0 \ln (2)\)
- D \(\frac{p_0 V_0\left(2^{1 / \gamma}-1\right)}{(\gamma-1)}\)
Answer & Solution
Correct Answer
(B) \(\frac{p_0 V_0\left(2^{1 / \gamma}-2\right)}{(1-\gamma)}\)
Step-by-step Solution
Detailed explanation
We know that, adiabatic relation, \( p V^\gamma=\text { constant } \) For adiabatic process \(A \rightarrow B\) \( \begin{aligned} 2 p_0 V_0^\gamma & =p_0 V_1^\gamma \\ \Rightarrow \quad V_1^\gamma & =2 V_0^\gamma \Rightarrow V_1=2^{1 / \gamma} V_0 \end{aligned} \)…
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