TS EAMCET · Physics · Current Electricity
The potential difference \(V\) across the filament of the bulb shown in the given Wheatstone bridge varies as \(V=i(2 i+1)\), where ' \(t\) ' is the current in ampere through the filament of the bulb. The emf of the battery \(\left(V_{\mathrm{a}}\right)\) so that the bridge becomes balanced is
- A 10 V
- B 15 V
- C 18 V
- D 25 V
Answer & Solution
Correct Answer
(C) 18 V
Step-by-step Solution
Detailed explanation
Condition for wheatstone: \(\frac{R_1}{R_2}=\frac{R_4}{R_3}\) \(\begin{aligned} & =\frac{4}{B}=\frac{8}{12} \\ B & =\frac{4 \times 12}{8} \\ \therefore R_{B} & =6 \Omega \end{aligned}\) Using Ohm's Law: And,…
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