TS EAMCET · Physics · Waves and Sound
The path difference between two particles of a sound wave is 50 cm and the phase difference between them is \(1.8 \pi\). If the speed of sound in air is \(340 \mathrm{~ms}^{-1}\), the frequency of the sound wave is
- A 672 Hz
- B 306 Hz
- C 612 Hz
- D 340 Hz
Answer & Solution
Correct Answer
(C) 612 Hz
Step-by-step Solution
Detailed explanation
For sound wave, \(\Delta x=50 \mathrm{~cm}, \Delta \phi=1.8 \pi\) \(\therefore\) Path difference, \(\Delta x=\frac{\lambda}{2 \pi} \cdot \Delta \phi\) \(\Rightarrow \quad 50=\frac{\lambda}{2 \pi} \times 1.8 \pi \therefore \lambda=\frac{500}{9} \mathrm{~cm}\) \(\therefore \quad\)…
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