TS EAMCET · Physics · Ray Optics
The angles of incidence and emergence of a light ray passing through a prism of angle \(A\) are \(i\) and e respectively. The total deviation produced by the prism is
- A \(\mathrm{i}+\mathrm{e}+\mathrm{A}\)
- B \(\mathrm{i}+\mathrm{e}-\mathrm{A}\)
- C \(\mathrm{i}+\mathrm{e}-2 \mathrm{~A}\)
- D \(\mathrm{i}+\mathrm{e}+2 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{i}+\mathrm{e}-\mathrm{A}\)
Step-by-step Solution
Detailed explanation
Total deviation is given by: \(\begin{aligned} & \delta=\theta_1+\theta_2 \\ & \delta=i-r_1+e-r_2 \\ & =i+e-\left(r_1+r_2\right) . \\ & \delta=i+e-A\end{aligned}\)
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