TS EAMCET · Physics · Center of Mass Momentum and Collision
A rocket motor consumes \(100 \mathrm{~kg}\) of fuel per second exhausting it with a speed of \(5 \mathrm{~km} / \mathrm{s}\). The speed of the rocket when its mass is reduced to \(\frac{1^{\text {th }}}{20}\) of its initial mass, is (Assume initial speed to be zero and ignored gravitational and viscous forces.)
- A \(20 \mathrm{~km} / \mathrm{s}\)
- B \(40 \ln (2) \mathrm{km} / \mathrm{s}\)
- C \(5 \ln (20) \mathrm{km} / \mathrm{s}\)
- D \(10 \mathrm{ln}(10) \mathrm{km} / \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(5 \ln (20) \mathrm{km} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Key Idea Velocity of a rocket at any timet, \(v=u\left(\frac{m_0}{m}\right)-g t\) where, \(u=\) speed of exhausted gases, \(m_0=\) initial mass of the rocket and \(m=\) mass of the rocket at time \(t\) Given, fuel burned rate,…
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