TS EAMCET · Physics · Electrostatics
Two small conducting balls of identical mass \(20 \mathrm{~g}\) and identical charge \(10^{-10} \mathrm{C}\) hang from non-conducting threads of length, \(L=300 \mathrm{~cm}\). If the equilibrium separation of balls is \(x\) and \(x \ll L\) then the magnitude of \(x\) is (Assume, \(4 \pi \in_0=\frac{1}{9 \times 10^9} \mathrm{~F} / \mathrm{m}\) and \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(\frac{2}{5^{1 / 3}} \mathrm{~mm}\)
- B \(\frac{3}{10^{1 / 3}} \mathrm{~mm}\)
- C \(\frac{3^{1 / 3}}{10} \mathrm{~mm}\)
- D \(\frac{3^{2 / 3}}{5} \mathrm{~mm}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{10^{1 / 3}} \mathrm{~mm}\)
Step-by-step Solution
Detailed explanation
Given, mass of each spherical ball, \( m=20 \mathrm{~g}=2 \times 10^{-2} \mathrm{~kg}, g=10 \mathrm{~m} / \mathrm{s}^2 \) charge on each spherical ball, \( q_1=q_2=q=10^{-10} \mathrm{C} \) and length of thread, \( L=300 \mathrm{~cm}=3 \mathrm{~m} \) According to the question,…
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