TS EAMCET · Physics · Motion In Two Dimensions
A particle is moving in a circle of radius \(5 \mathrm{~cm}\) with uniform speed and completes the circle in \(5 \mathrm{~s}\). What is the magnitude of linear acceleration?
- A \(0.8 \pi^2 \mathrm{~cm} / \mathrm{s}^2\)
- B \(0.8 \pi^2 \mathrm{~m} / \mathrm{s}^2\)
- C \(0.8 \pi \mathrm{cm} / \mathrm{s}^2\)
- D \(0.8 \pi \mathrm{m} / \mathrm{s}^2\)
Answer & Solution
Correct Answer
(A) \(0.8 \pi^2 \mathrm{~cm} / \mathrm{s}^2\)
Step-by-step Solution
Detailed explanation
Radius of the circle, \(r=5 \mathrm{~cm}\) Time period, \(T=5 \mathrm{~s}\) \(\therefore \quad T=\frac{2 \pi}{\omega}\) (where, \(\omega\) is angular velocity.) \[ \Rightarrow \quad \omega=\frac{2 \pi}{5} \mathrm{rad} / \mathrm{s} \] \(\therefore\) Linear speed,…
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