TS EAMCET · Physics · Atomic Physics
The ratio of the kinetic energies of the electrons in the third and fourth excited states of hydrogen atom is
- A \(4: 3\)
- B \(16: 9\)
- C \(25: 16\)
- D \(5: 4\)
Answer & Solution
Correct Answer
(C) \(25: 16\)
Step-by-step Solution
Detailed explanation
For the third excited state, \(n_1 = 4\). For the fourth excited state, \(n_2 = 5\). Kinetic energy \(K \propto \frac{1}{n^2}\). \(\frac{K_1}{K_2} = \frac{n_2^2}{n_1^2}\) \(\frac{K_1}{K_2} = \frac{5^2}{4^2} = \frac{25}{16}\)
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