TS EAMCET · Physics · Kinetic Theory of Gases
A vessel contains hydrogen and nitrogen gases in the ratio \(2: 3\) by mass. If the temperature of the mixture of the gases is \(30^{\circ} \mathrm{C}\), then the ratio of the average kinetic energies per molecule of hydrogen and nitrogen gases is (Molecular mass of hydrogen gas \(=2\) and molecular mass of nitrogen gas \(=28\))
- A \(3: 7\)
- B \(2: 3\)
- C \(1: 1\)
- D \(1: 14\)
Answer & Solution
Correct Answer
(C) \(1: 1\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{m}_{\mathrm{H}_2}=\mathrm{m}_{\mathrm{N}_2}=2: 3, \mathrm{~T}_{\text {mixture }}=\mathrm{T}_{\mathrm{H}_2}=\mathrm{T}_{\mathrm{N}_2}=30^{\circ} \mathrm{C} \\ \therefore \quad & \lt \mathrm{KE}\gt/ \text { molecule }=\frac{\mathrm{f}}{2}…
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