ExamBro
ExamBro
TS EAMCET · Physics · Motion In Two Dimensions

An object of mass \(2 m\) is projected with a speed of \(100 \mathrm{~ms}^{-1}\) at an angle \(\theta=\sin ^{-1}\left(\frac{3}{5}\right)\) to the horizontal. At the highest point, the object breaks into two pieces of same mass \(m\) and the first one comes to rest. The distance between the point of projection and the point of landing of the bigger piece (in metre) is (Given, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )

  1. A \(3840\)
  2. B \(1280\)
  3. C \(1440\)
  4. D \(960\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1440\)

Step-by-step Solution

Detailed explanation

Horizontal range of the object fired, \(R=\frac{u^2 \sin 2 \theta}{g}\) At the highest point, when object is exploded into two equal masses, then \(2 m u \cos \theta=m(0)+m v\) or \(v=2 u \cos \theta\) It means, the horizontal velocity becomes double at the highest point, hence…
Same subject
Explore more questions on app