TS EAMCET · Physics · Thermal Properties of Matter
Three rods \(A B, B C\) and \(B D\) made of the same material and having the same cross-section have been joined as shown in the figure.
The ends \(A, C\) and \(D\) are held at temperatures of \(20^{\circ} \mathrm{C}, 80^{\circ} \mathrm{C}\) and \(80^{\circ} \mathrm{C}\) respectively. If each rod is of same length, then the temperature at the junction \(B\) of the three rods is
- A \(90^{\circ} \mathrm{C}\)
- B \(60^{\circ} \mathrm{C}\)
- C \(40^{\circ} \mathrm{C}\)
- D \(30^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(60^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Let the temperature of function \(\theta\). Since, \(\operatorname{rod} B C\) and \(B D\) are parallel to each other (because both having the same temperature difference). Hence, given figure can be redrawn as follows ( \(R\) be the resistance of each rod).…
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