TS EAMCET · Physics · Electrostatics
A small block of mass \(5 \mathrm{~g}\) and charge \(5 \mu \mathrm{C}\) is placed on insulated, frictionless, inclined plane of angle \(60^{\circ}\). An electric field is applied parallel to the inclined plane. If the block remains at rest then the magnitude of electric field is \(\left[\right.\) Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\))
- A \(\frac{10^5}{\sqrt{3}} \mathrm{~N} / \mathrm{C}\)
- B \(\frac{5}{\sqrt{3}} \times 10^4 \mathrm{~N} / \mathrm{C}\)
- C \(\frac{\sqrt{3}}{2} \times 10^4 \mathrm{~N} / \mathrm{C}\)
- D \(2 \times 10^4 \mathrm{~N} / \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(\frac{\sqrt{3}}{2} \times 10^4 \mathrm{~N} / \mathrm{C}\)
Step-by-step Solution
Detailed explanation
As block is at rest So, \(\mathrm{qE}=\mathrm{mg} \sin \theta\)…
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