TS EAMCET · Physics · Mechanical Properties of Fluids
Eight spherical rain drops of the same mass and radius are falling down with a terminal speed of \(6 \mathrm{~cm}-\mathrm{s}^{-1}\). If they coalesce to form one big drop, what will be the terminal speed of bigger drop? (Neglect the buoyancy of the air)
- A \(1.5 \mathrm{~cm}^{-1} \mathrm{~s}^{-1}\)
- B \(6 \mathrm{~cm}_{-\mathrm{s}^{-1}}\)
- C \(24 \mathrm{~cm}^{-1} \mathrm{~s}^{-1}\)
- D \(32 \mathrm{~cm}^{-1} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.5 \mathrm{~cm}^{-1} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
Let now radius of big drop is \(R\). Then, \(\begin{aligned} \frac{4}{3} \pi R^3 & =\frac{4}{3} \times \pi r^3 \cdot 8 \\ R & =2 r \end{aligned}\) where \(r\) is radius of small drops. Now, terminal velocity of drop in liquid.…
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