TS EAMCET · Physics · Nuclear Physics
The average energy of a neutron produced in the fission of \({ }_{92}^{235} \mathrm{U}\) is
- A \(160 \times 10^{-13} \mathrm{~J}\)
- B \(320 \times 10^{-15} \mathrm{~J}\)
- C \(320 \times 10^{-13} \mathrm{~J}\)
- D \(160 \times 10^{-15} \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(320 \times 10^{-15} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(1 \mathrm{~MeV} = 1.602 \times 10^{-13} \mathrm{~J}\) \(E_{\text{neutron}} \approx 2 \mathrm{~MeV}\) \(E_{\text{neutron}} = 2 \times 1.602 \times 10^{-13} \mathrm{~J} = 3.204 \times 10^{-13} \mathrm{~J}\) \(E_{\text{neutron}} \approx 320 \times 10^{-15} \mathrm{~J}\)
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