TS EAMCET · Physics · Motion In One Dimension
A vehicle starts moving in a straight line with an acceleration, \(a=4 \mathrm{~m} / \mathrm{s}^2\), with initial velocity equal to zero. After accelerating for time \(t_1\), the vehicle moves uniformly and for time \(t_2\), the vehicle finally decelerates for time \(t_1\) eventually coming to a stop. The total time taken during the motion is \(10 \mathrm{~s}\) and the average velocity during the motion is \(5.1 \mathrm{~m} / \mathrm{s}\). The time taken by the vehicle during acceleration is
- A \(2 \mathrm{~s}\)
- B \(2.5 \mathrm{~s}\)
- C \(1.5 \mathrm{~s}\)
- D \(1.8 \mathrm{~s}\)
Answer & Solution
Correct Answer
(C) \(1.5 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
For first part of journey, \(x=0, a=4 \mathrm{~ms}^{-2}\), time \(=t_1\). Velocity attained by particle at end of time \(t_1\) is \(\quad v_1=u+a t_1=4 t_1\) \(\therefore\) Displacement in first \(t_1\) seconds is…
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