TS EAMCET · Physics · Thermal Properties of Matter
On a new temperature scale, the melting point of ice is 20 \({ }^{\circ} \mathrm{X}\) and the boiling point of water is \(110^{\circ} \mathrm{X}\). A temperature of \(40^{\circ} \mathrm{C}\) would be indicated on this new temperature scale as
- A \(60 ^\circ X\)
- B \(56 ^\circ X\)
- C \(70 ^\circ X\)
- D \(54 ^\circ X\)
Answer & Solution
Correct Answer
(B) \(56 ^\circ X\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \frac{\text { Reading on new scale -LFP }}{\text { UFP - LFP }}=\frac{\mathrm{C}-0}{100} \\ & \frac{\mathrm{z}^{\circ} \mathrm{X}-20^{\circ} \mathrm{X}}{110^{\circ} \mathrm{X}-20^{\circ} \mathrm{X}}=\frac{40-0}{100} \Rightarrow \mathrm{z}^{\circ}…
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