TS EAMCET · Physics · Mathematics in Physics
A physical quantity \(X\) is given by \(X=\frac{2 k^3 l^2}{m \sqrt{n}}\). The percentage errors in the measurements of \(k, l, m\) and \(n\) are \(1 \%, 2 \%, 3 \%\) and \(4 \%\) respectively. The value of \(X\) is uncertain by
- A \(8 \%\)
- B \(10 \%\)
- C \(12 \%\)
- D \(14 \%\)
Answer & Solution
Correct Answer
(C) \(12 \%\)
Step-by-step Solution
Detailed explanation
Given quantity \(X=\frac{2 k^3 1^2}{m \sqrt{n}}\) and percentage error in the measurement of \(\mathrm{k}=1 \%, \mathrm{l}=2 \%, \mathrm{~m}=3 \%\) and \(\mathrm{n}=\) \(4 \%\) therefore value of \(\mathrm{X}\) is uncertain by \(3 \times 1+2 \times 2+1\)…
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