TS EAMCET · Physics · Center of Mass Momentum and Collision
A particle of mass \(M\) is moving in a horizontal circle of radius \(R\) with wiform speed \(v\). When the particle moves from one point to a diametrically opposite point, its
- A momentum does not change
- B momentum changes by \(2 M N\)
- C kinetic energy changes by \(\frac{\mathrm{MV}^2}{4}\)
- D kinetic energy changes by \(M V^2\)
Answer & Solution
Correct Answer
(B) momentum changes by \(2 M N\)
Step-by-step Solution
Detailed explanation
Given, Velocity of particle \(=v\) Change in momentum = final momentum - initial momentum \(=M v-(-M v)=2 M v\)
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