TS EAMCET · Physics · Motion In Two Dimensions
The angular speed of a particle moving in a circular path is doubled. Then, the centripetal acceleration of the particle is
- A 4 times the initial centripteal acceleration
- B halved
- C doubled
- D unchanged
Answer & Solution
Correct Answer
(A) 4 times the initial centripteal acceleration
Step-by-step Solution
Detailed explanation
Angular speed, \(\omega=2 \omega\) \(\begin{aligned} & \frac{a_1}{a_2}=\frac{R \omega_1^2}{R \omega_2^2} \\ & \Rightarrow \frac{a_1}{a_2}=\frac{R \omega^2}{R(2 \omega)^2} \end{aligned}\)…
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