TS EAMCET · Physics · Electromagnetic Induction
A coil of resistance \(16 \Omega\) is placed with its plane perpendicular to a uniform magnetic field whose flux ( \(\phi\) in \(10^{-3}\) weber) changes with time ( t in second) as \(\phi=5 \mathrm{t}^2+4 \mathrm{t}+2\). The induced current at time \(t=6\) seconds is
- A 4 mA
- B 2.12 mA
- C 34 mA
- D 74 mA
Answer & Solution
Correct Answer
(A) 4 mA
Step-by-step Solution
Detailed explanation
\( \frac{d\phi}{dt} = \frac{d}{dt} (5t^2 + 4t + 2) \times 10^{-3} = (10t + 4) \times 10^{-3} \) V \( \varepsilon = \left| \frac{d\phi}{dt} \right|_{t=6} = (10 \times 6 + 4) \times 10^{-3} = 64 \times 10^{-3} \) V…
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