TS EAMCET · Physics · Work Power Energy
A particle of mass is moving along a circle of radius such that its tangential acceleration varies with distance covered as , where is a constant. The kinetic energy of the particle varies with the distance as , where and are constants. The values of and are
- A
- B
- C
- D
Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
Given, Tangential acceleration, at=αx2 and Kinetic energy, K=βxc. If F is the tangential force acting on the particle thenF=mαx2 Now applying work energy theorem, W=∆KE ⇒ ∫F dx=K ⇒ ∫mαx2dx=K…
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