TS EAMCET · Physics · Thermal Properties of Matter
A metal ball of mass \(1 \mathrm{~kg}\) is heated using a \(40 \mathrm{~W}\) heated in a room at \(30^{\circ} \mathrm{C}\). The temperature of the ball becomes stady at \(70^{\circ} \mathrm{C}\). Assuming Newton's law of cooling, the rate of loss of heat to the surrounding when the ball is at \(40^{\circ} \mathrm{C}\) is
- A 20 W
- B 5 W
- C 25 W
- D 10 W
Answer & Solution
Correct Answer
(D) 10 W
Step-by-step Solution
Detailed explanation
Mass of the ball, \(m=1 \mathrm{~kg}\) Power of the heater, \(P=40 \mathrm{~W}\) Room temperature, \(T_0=30^{\circ} \mathrm{C}\) and \(T=70^{\circ} \mathrm{C}\) By Newton's law of cooling, \(\frac{d Q}{d t}=k\left(T-T_0\right)\)…
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