TS EAMCET · Physics · Laws of Motion
A mass \(M \mathrm{~kg}\) is suspended by a weightless string. The horizontal force required to hold the mass at \(60^{\circ}\) with the vertical is
- A \(M g\)
- B \(M g \sqrt{3}\)
- C \(M g(\sqrt{3}+1)\)
- D \(\frac{M g}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(B) \(M g \sqrt{3}\)
Step-by-step Solution
Detailed explanation
By Newton's law \[ \begin{gathered} F=T \sin \theta \\ M g=T \cos \theta \end{gathered} \] Dividing Eq. (i) by Eq. (ii), we get…
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