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TS EAMCET · Physics · Oscillations

A small sphere of radius \(r\) is placed as a concave surface of radius of curvature \(R\) a little away from the centre. When the sphere is released, it oscillates. Assuming, the oscillation to be simple harmonic motion and \(r< < R\), then the time period is

  1. A \(2 \pi \sqrt{\frac{R}{g}}\)
  2. B \(2 \pi \sqrt{\frac{3 R}{2 g}}\)
  3. C \(2 \pi \sqrt{\frac{2 R}{3 g}}\)
  4. D \(2 \pi \sqrt{\frac{R}{2 g}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \pi \sqrt{\frac{R}{g}}\)

Step-by-step Solution

Detailed explanation

The motion of sphere is as shown in figure As, the sphere has simple harmonic motion on a curved surface, which is equivalent to the motion of pendulum. So, its time period is \(T=2 \pi \sqrt{\frac{l}{g}}\) Here, \(l=R\) \(\therefore \quad T=2 \pi \sqrt{\frac{R}{g}}\)
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