TS EAMCET · Physics · Mathematics in Physics
The position vector of a particle moving in a plane is given by \(\mathbf{r}=a \cos \omega t \hat{\mathbf{i}}+b \sin \omega t \hat{\mathbf{j}}\), where \(\hat{\mathbf{i}}\) and \(\hat{\mathbf{j}}\) are the unit vectors along the rectangular axes \(X\) and \(Y ; a, b\) and \(\omega\) are constants and \(t\) is time. The acceleration of the particle is directed along the vector
- A \(-a \hat{\mathbf{i}}+b \hat{\mathbf{j}}\)
- B \(b \hat{\mathbf{i}}+a \hat{\mathbf{j}}\)
- C \(-r\)
- D \(\frac{d r}{d t}\)
Answer & Solution
Correct Answer
(C) \(-r\)
Step-by-step Solution
Detailed explanation
Given, position vector, \(\mathbf{r}=a \cos \omega \hat{\mathbf{i}}+b \sin \omega \hat{\mathbf{j}}\) On differentiating both sides w.r.t. \(t\), we get Velocity,…
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