TS EAMCET · Physics · Electrostatics
A circular wire loop of radius \(1 \mathrm{~cm}\) carries a total charge \(1 \times 10^{-6} \mathrm{C}\) distributed uniformly over its length. If \(0.01 \%\) of its length (circumference) is cut-off, then the electric field at the centre of the loop due to the remaining wire is \[ \left(\text { Take, } \frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \text { SI unit }\right) \]
- A \(3 \times 10^3 \mathrm{~N} / \mathrm{C}\)
- B \(6 \times 10^3 \mathrm{~N} / \mathrm{C}\)
- C \(9 \times 10^3 \mathrm{~N} / \mathrm{C}\)
- D \(1.2 \times 10^2 \mathrm{~N} / \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(9 \times 10^3 \mathrm{~N} / \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Radius of the loop, \(r=1 \mathrm{~cm}=0.01 \mathrm{~m}\) Total charge on the loop, \(Q=1 \times 10^{-6} \mathrm{C}\)…
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