TS EAMCET · Physics · Electromagnetic Induction
A rectangular loop of wire is placed in the \(X Y\)-plane with its side of length \(3 \mathrm{~cm}\) parallel to the \(X\)-axis and the side of length \(4 \mathrm{~cm}\) parallel to the \(Y\)-axis. It is moving in the positive \(X\)-direction with the speed \(10 \mathrm{~cm} / \mathrm{s}\). A magnetic field exists in the space with its direction parallel to the \(Z\)-axis. The field decreases by \(2 \times 10^{-3} \mathrm{~T} / \mathrm{cm}\) along the positive \(X\)-axis and increases in time by \(2 \times 10^{-2} \mathrm{~T} / \mathrm{s}\). The induced emf in the wire is
- A \(-4.8 \times 10^{-5} \mathrm{~V}\)
- B \(4.8 \times 10^{-5} \mathrm{~V}\)
- C 0
- D \(3.6 \times 10^{-5} \mathrm{~V}\)
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
Induced emf in wire = Rate of change of flux…
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