TS EAMCET · Physics · Electrostatics
A clock dial has point charges \(-\mathrm{q},-2 \mathrm{q},-3 \mathrm{q}, \ldots \ldots \ldots .-12 \mathrm{q}\) at the positions of the corresponding numbers on the dial respectively. The time at which the hour's hand points the direction of the net electric field at the centre of the dial is (Assume clock hands do not influence the net electric (field)
- A \(8:30\)
- B \(9:30\)
- C \(10:30\)
- D \(12:30\)
Answer & Solution
Correct Answer
(B) \(9:30\)
Step-by-step Solution
Detailed explanation
Electric field is given by \(\mathrm{E}=\frac{\mathrm{Kq}}{\mathrm{r}^2}\) Charge is more then electric field is also more. \(\therefore \mathrm{E}_1=\mathrm{E}_2=\mathrm{E}_3=\mathrm{E}_4=\mathrm{E}_5=\mathrm{E}_6=\mathrm{E}\) The magnitude of two vector and their resuiant is…
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