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TS EAMCET · Physics · Motion In One Dimension

Two towns \(\mathrm{X}\) and \(\mathrm{Y}\) are connected by a regular bus service. A bus leaves in either direction at every \(t=T\) minutes. A man moving with some speed in the direction \(\mathrm{X}\) to \(\mathrm{Y}\) finds that a bus goes past him every \(t=t_1\) minutes in the direction of his motion, and every \(t=t_2\) minutes in the opposite direction. Then \(T\) is given by

  1. A \(\frac{2 t_1 t_2}{t_1+t_2}\)
  2. B \(\frac{\left(t_1-t_2\right) t_1}{t_1+t_2}\)
  3. C \(\frac{2 t_2\left(t_1+t_2\right)}{\left|t_1+t_2\right|}\)
  4. D \(\frac{t_1 t_2}{\left|t_1-t_2\right|}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{2 t_1 t_2}{t_1+t_2}\)

Step-by-step Solution

Detailed explanation

Let \(\mathrm{V}\) be the speed of bus running between towns \(\mathrm{A}\) and \(\mathrm{B}\). And, speed of the man \(=\mathrm{V}_{\mathrm{o}}\) Relative speed of the bus moving in the direction of man \(=\mathrm{V}-\mathrm{V}_{\mathrm{o}}\) As bus went pass the man every…
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