TS EAMCET · Physics · Center of Mass Momentum and Collision
Two particles of equal mass have velocities \(\overrightarrow{\mathbf{v}}_1=4 \hat{\mathbf{i}}\) and \(\overrightarrow{\mathbf{v}}_2=4 \hat{\mathbf{j}} \mathrm{ms}^{-1}\). First particle has an acceleration \(\overrightarrow{\mathbf{a}}_1=(5 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}) \mathrm{ms}^{-2}\) while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of
- A straight line
- B parabola
- C circle
- D ellipse
Answer & Solution
Correct Answer
(A) straight line
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathbf{v}_{\mathrm{CM}}=\frac{m_1 \mathbf{v}_1+m_2 \mathbf{v}_2}{m_1+m_2} \\ & =\frac{\mathbf{v}_1+\mathbf{v}_2}{2}\left(\text { as } m_1=m_2\right) \\ & \text { and } \mathbf{a}_{\mathrm{CM}}=\frac{m_1 \mathbf{a}_1+m_2…
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