TS EAMCET · Physics · Thermal Properties of Matter
A body cools from a temperature of \(60^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\) in 10 minutes and \(50^{\circ} \mathrm{C}\) to \(40^{\circ} \mathrm{C}\) in 15 minutes. The time taken in minutes for the body to cool from \(40^{\circ} \mathrm{C}\) to \(30^{\circ} \mathrm{C}\) is
- A \(30\)
- B \(20\)
- C \(25\)
- D \(40\)
Answer & Solution
Correct Answer
(A) \(30\)
Step-by-step Solution
Detailed explanation
\( \frac{60-50}{10} = k\left(\frac{60+50}{2}-T_s\right) \Rightarrow 1 = k(55-T_s) \) \( \frac{50-40}{15} = k\left(\frac{50+40}{2}-T_s\right) \Rightarrow \frac{2}{3} = k(45-T_s) \)…
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