TS EAMCET · Physics · Laws of Motion
A cyclist leans with the horizontal at angle \(30^{\circ}\), while negotiating round a circular road of radius \(20 \sqrt{3} \mathrm{~m}\). The speed of the cycle should be
- A \(7 \sqrt{3} \mathrm{~m} / \mathrm{s}\)
- B \(14 \mathrm{~m} / \mathrm{s}\)
- C \(7 \sqrt{6} \mathrm{~m} / \mathrm{s}\)
- D \(10 \sqrt{6} \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(D) \(10 \sqrt{6} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
According to the question, the situation is as shown below Balancing the forces, \(N \sin 30^{\circ}=m g\) \(\ldots(\mathrm{i})\) \(\text { and } \quad N \cos 30^{\circ}=\frac{m v^2}{R}\) \(\ldots(\mathrm{ii})\) Dividing Eq. (i) by Eq. (ii), we get…
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