TS EAMCET · Physics · Work Power Energy
A force acts on a body of mass \(10 \mathrm{~kg}\), resulting in its displacement given as \(x=\left(\frac{t^3}{25}\right) \mathrm{m}\), where \(t\) is the time in seconds. The work done by the force in \(1 \mathrm{~s}\) is
- A 620 J
- B 333 J
- C 524 J
- D 60 J
Answer & Solution
Correct Answer
(D) 60 J
Step-by-step Solution
Detailed explanation
Given, displacement, \(x=\frac{t^3}{25}\) So, velocity, \(v=\frac{d x}{d t}=\frac{3 t^2}{25} \mathrm{~ms}^{-1}\) Acceleration, \(a=\frac{d v}{d t}=\frac{6 t}{25} \mathrm{~ms}^{-2}\) Force \(=\) Mass \(\times\) Acceleration…
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